I had a wild experience at one of the Indiana riverboats this past Friday. The bj tables were crowded, so I played straight bj at a 21 + 3 sidebet table (6d, s17, das, etc.) Because I was having a good session and had been watching the other ploppies loosing at bj but making money on the side bet - I played the side bet for the first time (the tc was +8 and I thought I might catch some faces with only two other players). (yes, I know the house has a 5%+ advantage on this bet). Here is what happened -
first side bet -10$ - J,K dealer Q win $90 dealer bust
next hand side bet - 45$ - 10,10 and dealer 10 win $405 dealer push
next hand side bet - 45$ - 8,9 and dealer 10 win $405 dealer 19
and then believing this could never happen 4 times in a row, I was dealt an A,K
snapper with the dealer showing a queen. Unfortunately I didn't play the side
bet, not even for the rest of the night. My question?
What are the approximate odds of getting a winning side bet on 4 consecutive hands from a 6 deck shoe? Approximately .1 x .1 x.1 x.1 = 1 in 10,000?
first side bet -10$ - J,K dealer Q win $90 dealer bust
next hand side bet - 45$ - 10,10 and dealer 10 win $405 dealer push
next hand side bet - 45$ - 8,9 and dealer 10 win $405 dealer 19
and then believing this could never happen 4 times in a row, I was dealt an A,K
snapper with the dealer showing a queen. Unfortunately I didn't play the side
bet, not even for the rest of the night. My question?
What are the approximate odds of getting a winning side bet on 4 consecutive hands from a 6 deck shoe? Approximately .1 x .1 x.1 x.1 = 1 in 10,000?