2D vs 6D: Both -.48

[jack.jackson]

From what i understand a BS player will lose on average the same amount in the long run regardless of whitch game hes playing. Regardless of rules in play, pen, and numbers of players, assuming perfect basic strategy and flatbetting of course. Of course it would have to have different rules. But that should be irrelevant if your e.vs are both -.48.

Now lets assume, two different card counters playing each one of these
games. To illustrate my example, lets say their both using the same system, heads up with the dealer, and both using a 1:12 spread. Penetration wise thier will be one deck left in each of the -.48 games. Play all.

Besides the 2D game being easier to count. Whitch game would yield more
when we integrate card counting? Would the results be the same? Or would the 2D game yield more because the count will spike more often.
Therefore allowing us take advantage of a positive situation more often than the 6D game. Or would the 50% pen in the 2D yeild less than the 83.3% pen in the 6D game.

 

[Sonny]

Or would the 50% pen in the 2D yeild less than the 83.3% pen in the 6D game.

The game with the deeper penetration will produce more high counts and will therefore earn more than the game with shallow penetration. That is why penetration is usually the most important factor in the game.

-Sonny-

 

[Kasi]

The game with the deeper penetration will produce more high counts -Sonny-

I don't know about games with the same house edge, or expected yield with the same betting scheme (or even how u could spread 1-12 at the same TC's in a 52/104 game), but I think a 52/104 S17 DAS will have more TC>=+1 counts than a 5/6 game with the same rules.

Like 6 decks would have more counts at TC+1 but fewer than 2D at some higher +TC's. But fewer overall.

Almost certainly your unit size would be different for each game with the same spread, even if u could spread the same, wouldn't it?

What rules would equal the same house edge?

 

[moo321]

I would take the 5/6 6-deck game over the 52/104 2-deck game. Back-count it.

 

[jack.jackson]

I don't know about games with the same house edge, or expected yield with the same betting scheme (or even how u could spread 1-12 at the same TC's in a 52/104 game), but I think a 52/104 S17 DAS will have more TC>=+1 counts than a 5/6 game with the same rules.

Like 6 decks would have more counts at TC+1 but fewer than 2D at some higher +TC's. But fewer overall.

Almost certainly your unit size would be different for each game with the same spread, even if u could spread the same, wouldn't it?

What rules would equal the same house edge?

6D, S17,LS,NDAS,DOA, -.48

2D ,H17,LS,NDAS,DOA, -.49

So basically if you H17 in a 2D its the same e.v compared to a S17 6D if all other rules are the same! Nevertheless theres other combinations that will produce axp. the same e.v.

Im not sure what you were trying to say there. But as far as im concerned the same spread and scheme could be used in either game. Remember, different schemes are optional!

But overall i think i would have to agree with your conclusion in a play all game.
For one our p.e would be far surperior in a 2D and since were playing heads up that should make a significant difference.
Two we would see positive counts more often allowing us to see more action.

However i could see why that 5/6 game could possibly be better as well.

More than likely its probably to close to tell anyway. Or impossible.

Thanks for all the responses. J.J

 

[Sonny]

6D, S17,LS,NDAS,DOA, -.48

2D ,H17,LS,NDAS,DOA, -.49

Based on Schlesinger's charts, the DD game will see about 26.6 hands at +1 or more while the 6D game will see 28.1 hands.With a 1:8 spread the DD player will earn 1.18 units per hour while the 6D player earns 1.28 units per hour. The risk of ruin for the 6D player is also about 1% lower for an 800-unit bankroll.


-Sonny-