4 Aces removed from 6D game

[matt21]

Assume normal HE (if all 24 aces were present) for the game is 0.5%.

For a BS player, what is the HE off the top if 4 aces have been removed from a 6d shoe?

Thanks in advance,
Matt21

 

[Jack_Black]

.005816*4=.0232

-.0232-.5=-.523

http://wizardofodds.com/blackjack/appendix7.html

 

[BrianCP]

I got minus .9 percent using this optimal calculator thingy. I think it calculates that assuming optimal play based on the exact cards left though, so probably just a tiny bit worse than that.

 

[21forme]

Correction to JB above:
1. The EOR for 1 ace per deck is -0.005816, so that times 4/6 = -0.0038773
2. Assumed HE 0.5% = -.005
3. Add the two together = -0.0088783 => 0.89% house edge.

 

[MangoJ]

The Wizard's table states the EV correction for a removed card is per deck. Hence with 4 aces are removed from six decks, that means 2/3 aces removed per deck.
EV correction would be 2/3*-0.005816 = -0.388%.

Total EV on top is then estimated to -0.888% = ~-0.9%.

 

[matt21]

tahnks for the prompt replies guys. i'll go with 0.9% then. :grin:

 

[sagefr0g]

hey Matt, for a h17,das,lsr,(rsa-3) six deck game see results for kc's tdca for full pack (-0.4736) and for pack with 4 aces removed (-0.8457) below: