6D multi position math

[Stealth Bomber]

Let's assume for instance the game is 6D, 80% pen, +15TC, two aces extra on average left in the pack and 4.? decks have already gone to the discard tray. Let's also assume in this situation that there is on average 16 play positions left in the pack to be played before the shoe is over and the pit crew doesn't have a care in the world about us being AP's or how many hands we play and we have a truck load of $ for a bk-roll. Now let's also assume we will be playing 1 on 1 in any of the following manners to finish out the shoe:

1) play one position with a total of eight hands to the D and eight hands to the player -or-

2) play three positions with a total of four hands to the D and twelve to the player -or-

3) play seven positions with a total of two hands to the D and fourteen to the player.

Which option would mathematically provide the highest EV?

 

[The Mayor]

Just guessing

*choice 1 is the best if the table max is above your bankroll max bet.

*choice 3 is best if your bankroll is such that you can bet the table max on each spot.

Choice 1: Rounds reduce variance, so you are best to go for the greatest number of rounds. You will get the same EV, but much lower variance, by seeing several dealer hands.

Choice 3: has extremely high variance, and that can only be justified if you can put a huge amount on the table to increase your EV accordingly. Normally this is not how we play, as we spread to multiple hands we reduce the overall bet size as we place each additional bet. Thus, to justify this method, your bankroll would have to be such that your max bet is significantly higher than the table max.

 

[Stealth Bomber]

Sounds understandably correct

For the moment though, let's set aside any issues of NOT having plenty of bank-roll or any variance issues and just consider the math for the ROI or EV.

Regarding option #3 in my post above: play seven positions with a total of two hands to the D and fourteen to the player rather than just 1 on 1 play with our bets in only one circle playing one hand at a time.

I partly see option #3 as a defensive type play. More hands during a high C equal less BJ's for the D and more 3/2 BJ's for the player. It is just my own theory that the EV should be higher for each additional position put into play while the C is so high. In this situation, the player will get more BJ's, (I believe the ratio is 8 to 1) which of course pay the player 3 to 2.

Why let the D have any more of the big cards than we absolutely have to? Why not use them in our own hands and take all we can get while the opportunity is there?