phantom007
Well-Known Member
In the very near future, I will be playing in a BJ tourney along with 249 others. Buy-in $500....but total prize pool = $150k...therefore players providing 5/6th of pool, with casino kicking in $25k.
No Re-buy-in in this one. After 2 rounds of #25 hands each, top 36 players go to the semi-finals...winner of each of these 6 tables, plus one Wildcard, occupy the Final table.
Pay-offs are roughly as follows:
---1st...60k
---2nd...25k
---3rd...20k
---4th...13k
---5th...7k
---6th...4.5k
---7th-36th...$500 each
---Wild-Card player gets 3.5k plus seat at the final table.
---All get 2 nights free room, 2 meals, and a free gift
---#4 players will be drawn to receive free entry into next tourney (value 2k).
In my simple mind, EV is about +21%, albeit that one will have only a 7/250 chance of being "way" ahead, a 34/250 chance of "being even + free stuff", and a 209/250 chance of having a $500. dollar T-shirt.
Is my math logic correct?
Thanks
Phantom007.
No Re-buy-in in this one. After 2 rounds of #25 hands each, top 36 players go to the semi-finals...winner of each of these 6 tables, plus one Wildcard, occupy the Final table.
Pay-offs are roughly as follows:
---1st...60k
---2nd...25k
---3rd...20k
---4th...13k
---5th...7k
---6th...4.5k
---7th-36th...$500 each
---Wild-Card player gets 3.5k plus seat at the final table.
---All get 2 nights free room, 2 meals, and a free gift
---#4 players will be drawn to receive free entry into next tourney (value 2k).
In my simple mind, EV is about +21%, albeit that one will have only a 7/250 chance of being "way" ahead, a 34/250 chance of "being even + free stuff", and a 209/250 chance of having a $500. dollar T-shirt.
Is my math logic correct?
Thanks
Phantom007.