BS question

[21gunsalute]

6 decks, H17, DAS, No Surrender, Peek

What is the rational for doubling 11 against a dealer Ace under these rules but not doubling the same if playing S17? I see the logic in every other basic strategy play I believe, but this is one that seems backwards to me. If the dealer is getting an advantage by hitting soft 17 why throw more money at a disadvantageous situation? And if it's not considered to be a disadvantageous situation then why not double 11 against an Ace when the dealer stands on soft 17? This makes no sense to me.

 

[FLASH1296]

The dealer's "bust rate" (how often the dealer will go over 21) for an
ACE up-card is higher in a H17 game then it is in a S17 game.

When you double a hand you have two ways to win.

The dealer's bust rate plays into whether or not a specific hand is a doubling hand;
especially when the hand is weak when it does not improve, such as a "soft" hand.

 

[21gunsalute]

Okay. I guess that makes sense. It must be a borderline call in both scenarios then I guess.

 

[FLASH1296]

Yes, it is a close call.

Typically the S17 shoe game will have an index for doubling 11 vs. Ace
at either +1 or +2 and ZERO or −1 for the H17 shoe game.