House edge under strange circumstances

JohnCrover

Banned
Hello, I have a purely theoretical question:
What would the house edge be if doubles and splits weren't paid but the player did not deviate from basic strategy?
Example: 11 Vs 6 for $100. Player doubles for $100, wins the hand. The player is only paid $100.
Example 2: 11 Vs 6 for $100. Player doubles for $100, losses the hand but only $100 is collected (not the full $200).
Just wondering what the house edge would be under these circumstances. Thank you.
 

DSchles

Well-Known Member
JohnCrover said:
Hello, I have a purely theoretical question:
What would the house edge be if doubles and splits weren't paid but the player did not deviate from basic strategy?
Example: 11 Vs 6 for $100. Player doubles for $100, wins the hand. The player is only paid $100.
Example 2: 11 Vs 6 for $100. Player doubles for $100, losses the hand but only $100 is collected (not the full $200).
Just wondering what the house edge would be under these circumstances. Thank you.
Just a question before I try to answer: If you don't get paid double, why would you double and give up your opportunity to tak emore than one card?

Don
 

DSchles

Well-Known Member
According to Peter Griffin, p. 19 of The Theory of Blackjack, proper doubling is worth 1.6% and pair splitting is worth 0.4%. So, together, 2.0%.

Don
 

JohnCrover

Banned
DSchles said:
Just a question before I try to answer: If you don't get paid double, why would you double and give up your opportunity to tak emore than one card?

Don
A purely theoretical question, thanks Don
 
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