Math Question

[Mr Pill]

If during a promotional period the following happened, what would be the effect on the house edge.

The game is: 6D S17 DA2 DAS Sp3 SpA1 LS FU AS DSA Pen is 75%

If during a promotional period of 4 hours they drew one card and during this period this was the "wild card". And if during this period you make a winning hand that contained this wild card you would get paid double your bet of up to $25.

What would the effect be on the EV of the game? To start with I believe the player EV of the game without the rule would be about -0.23%.

How is it calculated?

Thanks in advance,
Pill

 

[Rob McGarvey]

Only one card per 6 decks, or 1 card per deck is the payoff card??

 

[Automatic Monkey]

Just off the top of my head... if you have a wild card in your hand you have or will have an automatic 21. Let's say on the average you take 3 cards per hand, that's 3/52 times you will have this extra 21, or 5.77% of the time. Multiply that by the percentage of times the dealer doesn't have a 21, again by the percentage of times you would have had a 21 anyway, and again by 2 to factor in the 2:1 payoff, and you should have something like the correct answer.

 

[Mr Pill]

"Only one card per 6 decks, or 1 card per deck is the payoff card??"

The pit would draw a wild card from a standard 52 card deck. Say they drew the 4 of diamonds. During the promotional 4 hour period, the players would play from regular 6 deck shoes at the various tables. So each table would have 6 wild cards, in this case the six 4 of diamonds in each shoe.

When the player wins a hand, and if it contains the wild card, then they get paid double their wager. Also note just because the wild card shows up in your hand does not mean you win the hand, you still have to beat the dealer.

My assumption is also that some cards are better for the player to be "wild" than others. Some form of a 10 card being the best and a 5 card being the worst?

Pill

 

[Keith Jamison]

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