Thoughts on possible betting strategy

NDN21

Well-Known Member
I was thinking of using a different betting strategy for a 6-deck game (which is predominant in the places I can play in).

In the first 1.5 decks out of the shoe I would bet in order to optimize for risk of ruin, that is keep my risk of ruin at an acceptable level.

True count Bet size
1, 1
2, 2
3, 4
4, 8

(or something similar)

In the last playable 1.5 decks (2.5 to 2.75 decks actually still in shoe) the betting would be to optimize bankroll growth.

True count Bet size
1, 1
2, 6
3, 9
4, 10

Does anybody do anything like this? What would be a possible strategy for the middle 1.75-2.0 decks?
 
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Sonny

Well-Known Member
NDN21 said:
In the first 1.5 decks out of the shoe I would bet in order to optimize for risk of ruin...In the last playable 1.5 decks the betting would be to optimize bankroll growth.
Why not just use one betting strategy that is optimized for both? Using two different bet ramps is going to end up causing trouble. You are underbetting (and therefore under-earning) during your first phase and overbetting (therefore destroying your ROR) in your second phase. Whatever you achieve with one phase you destroy with the other. You would be better off optimizing your bet ramp for the fastest growth rate given a specific ROR. That is what proportional betting is all about.

-Sonny-
 
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Brock Windsor

Well-Known Member
Betting Schemes

I was recently sent an 8deck(DAS,DOA,S17) optimal betting strategy for Brh from Brett Harris and so far I've been pleased with the results. I've simplified it a bit for my own purposes and my mathematics are not strong enough to debate his theory of optimal bettings spreads with conviction, however it has worked well for my purposes. Preferably one spreads to two hands in +2 TC counts:
TC < 1 Bet 0
TC 1 Bet 1
TC 2 Bet One or Two hands of 2
TC 3 Bet One hand of 3.5 or Two hands of 3
TC 4 Bet One hand of 5 or Two hands of 4.25
TC 5 Bet One hand of 6.5 or Two hands of 5.5
TC > 6 Bet One hand of 7.5 or two hands of 6.5

Im sure the 6 deck would be slightly different but likely not by much.
BW
 
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NDN21 said:
I was thinking of using a different betting strategy for a 6-deck game (which is predominant in the places I can play in).

In the first 1.5 decks out of the shoe I would bet in order to optimize for risk of ruin, that is keep my risk of ruin at an acceptable level.

True count Bet size
1, 1
2, 2
3, 4
4, 8

(or something similar)

In the last playable 1.5 decks (2.5 to 2.75 decks actually still in shoe) the betting would be to optimize bankroll growth.

True count Bet size
1, 1
2, 6
3, 9
4, 10

Does anybody do anything like this? What would be a possible strategy for the middle 1.75-2.0 decks?
Whoa, wait, what's the theory behind this? The whole idea of true counting is that it then makes no difference what part of the shoe you are in; the true count is the true count.

In a 6D game, you don't get very many high counts at the beginning of the shoe. So consider yourself fortunate if you get a +4 TC in the first two decks of the shoe, and play it hard.
 

NDN21

Well-Known Member
Ok, that is what I will do.

This is why I posted the question before I actually did it, to get informed advice.

Thanks.
 

Kasi

Well-Known Member
Brock Windsor said:
I was recently sent an 8deck(DAS,DOA,S17) optimal betting strategy for Brh from Brett Harris and so far I've been pleased with the results. I've simplified it a bit for my own purposes and my mathematics are not strong enough to debate his theory of optimal bettings spreads with conviction, however it has worked well for my purposes. Preferably one spreads to two hands in +2 TC counts:
TC < 1 Bet 0
TC 1 Bet 1
TC 2 Bet One or Two hands of 2
TC 3 Bet One hand of 3.5 or Two hands of 3
TC 4 Bet One hand of 5 or Two hands of 4.25
TC 5 Bet One hand of 6.5 or Two hands of 5.5
TC > 6 Bet One hand of 7.5 or two hands of 6.5

Im sure the 6 deck would be slightly different but likely not by much.
BW

One OR 2? Like u have a choice?
Sounds crazy to me.
Don't see how 1 hand of 7.5 or 2 hands of 6.5 can be equal.
But good luck.
 
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