two hand wonging

steve

Active Member
I read an article a few years ago, not sure where I saw it, that discussed two hand wonging. Its premise was basically this: figure out your bet at TC = 2 based on your expectation and bankroll, then multiply that bet by 1.3 and divide that by 2 to get your per hand bet size with TC = 2, for any TC < 2, bet one hand of table minimum. The assumption was that you would play at a table where the table minimum would be significantly less than your optimal bet size at TC = 2.

Let's say you determine that your optimal bet size is $25 at a TC = 2, with two hands you can bet 30% more than that without increasing risk, round this off to $30, now play two hands of $15. For TC > 2 bet ((optimal bet size X (TC -1)) X 1.3) / 2 on each of two hands. For TC < 2 bet $5 (table minimum).

I used this approach a few times and I liked it because one of the things i hated about Wonging was constantly being on the prowl for a "good game", I liked being able to sit at one table and play without interruption.

Is anyone familiar with this approach?

Steve
 

zengrifter

Banned
Fairly standard, we won't need to go private with this - you can actually use +50%/2 - or for 3hands nearly +90%/3 - but the main detirminant for #hands played should take into account the #others in play. zg
 

CanKen

Well-Known Member
For more on this topic see a post by MathProf, reposted on "bjmath.com", called "Scoring the Shoe Strategies (Long)."
 
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