Understanding RoR with KO

p8ntballsk8r

Well-Known Member
So the book gives figures, and a graph, on 2 deck 1 to 5 spread. The type of game I am playing is 6 deck 1 to 10 spread.

Is my math correct in assuming that since 2 deck 1 to 5 spread using KO preferred is listed as 1.11, and that 6 deck 1-10 spread using KO preferred is listed as.73 advantage, that my game's figures will be skewed by 1.11/.73 or 1.52%?

so according to this assumption, playing KO preferred exactly by the book with a bankroll of 100 units, which has a 36% chance of ruin, would then be a 55% chance of ruin, and would be unprofitable?

similarly 1000 units brings the RoR from .5% to .76%

are these calculations correct, and if not, what is wrong with them, and what is the correct way to calculate it?
 

Mimosine

Well-Known Member
while i'm no expert, i have contemplated this issue as well.
i know someone on here could run a calculation for you.
looking at the other graphs in KO, like the "expectation" one, the slope is a lot steeper for the 1 and 2 deck games, hence the overall expectation is higher.

i always assumed (again, i have only just started studying this) that the ROR is LOWER in a 6 deck game, for the very reason that the expectation is lower.
less reward, less risk?
i'm not sure, but that is my first assumption based on the math, and graphs.

you calculations are wrong, because if you look carefully at the graph for 2 deck, one axis is logarithmic. The slope as well as the max/min values should change differently than by a simple integer relationship.

hopefully someone else will chime in. :)
 
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