Kasi said:
I have no idea lol - that's a job for k_c!
But the index number is +3 so maybe it would be a BS play since the number would be met (like with 234 or 252 kind of thing anyway maybe? lol).
My program doesn't accomodate Spanish 21 rules but it's not too hard to compute redouble by hand using the program output.
5-4 vs 7 standard single deck
1. Basic:
hit: +20.13%
double: +19.05%
2. 5-4-2 vs 7 (probability = 4/49) [This is the only case there's a difference between doubling and redoubling]
EV if doubled = stand EV = -46.76% * 2 * 4/49 = -7.63%
EV if redoubled = hit EV (draw 1 card <> set HSN=12) = +28.77% * 4 * 4/49 = +9.39%
3. double EV if redouble is allowed = (difference between doubling and redoubling)
= 19.05% - (-7.63%) + 9.39% = +36.07%, which is greater than +20.13%
I'm sure it would be right to double 6-3 and 7-2 as well so it would be right to double any hard 9. This is for a standard single deck and not a Spanish 21 deck.
I think this is right. Instead of having to accept a total of hard 11 on a doubled bet you would be allowed to bet 4 times your initial bet on a hard 11, if I understand the rule correctly.
k_c