somtum
Well-Known Member
Does anyone know how to mathematically test a card counting system and figure out it's indices?
I thought of a way of creating a balanced counting system using Ace's and Ten's both with a value of -1... though cards 2 through 9 wouldn't have a value of anything at all but the + counts would come from the ratio of cards that aren't Ace's and Ten's.
For assigning the plus counts I would use grouping of cards.. in a repeated pattern of
(3,2,3,2,3) again (3,2,3,2,3) etc... meaning after the first 3 cards dealt I assign +1... 2 cards dealt assign a +1 then 3 cards dealt and assign a +1 then 2 cards dealt assign a +1 then 3 cards dealt assign +1 ending the pattern..
Then I would start the pattern over again assigning a +1 after 3 more cards have been dealt and so on..
All that I know is that this would give an accurate ratio of combined 10's and Ace's in the deck..
For example if after a (5 7 9) (Q A) (2 7 K) (J J) (4 8 7) were dealt... it would be a running count of 0
The cards Q A K J J will total -5 in the running count by themselves
But the pattern of (3 cards, 2 cards, 3 cards, 2 cards, 3 cards) by themselves have a running count of +5.
I thought of a way of creating a balanced counting system using Ace's and Ten's both with a value of -1... though cards 2 through 9 wouldn't have a value of anything at all but the + counts would come from the ratio of cards that aren't Ace's and Ten's.
For assigning the plus counts I would use grouping of cards.. in a repeated pattern of
(3,2,3,2,3) again (3,2,3,2,3) etc... meaning after the first 3 cards dealt I assign +1... 2 cards dealt assign a +1 then 3 cards dealt and assign a +1 then 2 cards dealt assign a +1 then 3 cards dealt assign +1 ending the pattern..
Then I would start the pattern over again assigning a +1 after 3 more cards have been dealt and so on..
All that I know is that this would give an accurate ratio of combined 10's and Ace's in the deck..
For example if after a (5 7 9) (Q A) (2 7 K) (J J) (4 8 7) were dealt... it would be a running count of 0
The cards Q A K J J will total -5 in the running count by themselves
But the pattern of (3 cards, 2 cards, 3 cards, 2 cards, 3 cards) by themselves have a running count of +5.