Brilliant guess!then i think u don't agree with my strategy then
If you play ONE hand of $10 and win $70 dollars, that's 7 times your money. If you play 7 hands of $10 dollars and win $70, that's EVEN moneykeenen said:becuz... if we play NEVER BUST strategy.... that means we'll never bust right?
and if the dealer bust... we'll be 7times our initial bet....
we're using the same deck so that means we have the same pourcentage of winning..
if dealer stops at 17 .. it doesn't mean that he'll win all my 7 hands.... either 18,19,20, or even 21....
but once he bust... we'll win 7 hands...
so as i've tried.. it was..
1 st game + 7 ( dealer bust )
2 nd game + 4 ( win 2 lose 5 )
3 rd game + 5 ( win 4 lose 3 )
4 th game + 10.5 ( win 6 with Blackjack and lose one )
and so on....
i know that u don't agree with me.. but .. just wanna make sure..
cuz i've tried with 7 decks... and always the same way of playing....
Right, but you'll also never hit anything higher than 11 so you'll rarely have a decent hand. The only way you will win is if you are dealt a good hand in your first two cards or the dealer busts. In all other cases the dealer will beat you. That is why the house edge is as high as 4% for this strategy.keenen said:becuz... if we play NEVER BUST strategy.... that means we'll never bust right?
Nope. The dealer is hitting until he has a good hand while you are not. That means the dealer will win many more hands than you.keenen said:we're using the same deck so that means we have the same pourcentage of winning..
Unfortunately, the dealer does not bust often enough to make this a winning strategy. You will lose all 7 hands most of the time. The research has already been done and the sims have been run decades ago. This system does not work.keenen said:if dealer stops at 17 .. it doesn't mean that he'll win all my 7 hands.... either 18,19,20, or even 21....but once he bust... we'll win 7 hands...
i don't really understand what you trying to say... ? ^^tedloc said:If you play ONE hand of $10 and win $70 dollars, that's 7 times your money. If you play 7 hands of $10 dollars and win $70, that's EVEN money
What I'm saying is when you play 7 hands and win 7 hands, you have won EVEN money not 7 times your original bet......keenen said:i don't really understand what you trying to say... ? ^^
what do u mean by .. If i pay one hand of 10$ and win 70$ ( how can i win 70$ when i'm only playing 10$ )
what i'm trying to say is .. always play with the same amount of money without raise or decrease... ... always take when it's below 12... no matter what dealer has .... once i get over 11 ... then i stop.. ( never bust strategy )
so that means .. IF DEALER bust... ( without any exception ) bank has to PAY every hand ... but if dealer doesn't bust ... maybe he can get 17, 18, 19, 20 or even 21...... it doesn't mean all my 7 hands are LOSING... so in a long run.. i will win...? BUT I NEED MORE CALCULATION ( since it's ALL MATH ) need STATs professional
ya.. that's what i'm trying to say tootedloc said:What I'm saying is when you play 7 hands and win 7 hands, you have won EVEN money not 7 times your original bet......
Keenan, bud. This is is not really a topic for discussion. At house edge of 3.91% you will lose, no ifs ands or buts. Also, please take the following into consideration: BJ has been in America since the 20's. It is the biggest casino game played by millions every year, and casinos make 2 billion dollars a year from BJ alone. Do you really think if you just hit on 11 and below you can make money? That no one has ever thought about that? How do you think the casino pays it $3000 in wages and $1000 in electric bills every hour... because people are taking their money with that super BJ strategy? Let me throw one number at you. A dealers Ace only busts 17% of the time, after they check for BJ. That's 1 in 8 times. Now... do you still want to stay on that 12?mickpk said:Never bust: For my analysis of this strategy I assumed the player would never hit a hard 12 or more and based all other decisions on maximizing expected value under this assumption. This results in a house edge of 3.91%.
You said that you would win 7 times your initial bet when the dealer busts, but you won't. You will bet $70 (7 hands of $10 each) and you will win $70. That is an even money payout, not 7:1. In order to win 7 times your initial bet you would have to win $70 * 7 = $490 per round. Instead, you should expect to lose about $2.80 on each round because the house has such a huge advantage over you.keenen said:i don't really understand what you trying to say... ? ^^
what do u mean by .. If i pay one hand of 10$ and win 70$ ( how can i win 70$ when i'm only playing 10$ )
Sure, and eight-decker with one cut off! :laugh:bahoozle said:Anybody played 7 decks at a casino?
That's not true at all. The dealer will not bust 100% of the time. They will probably only bust about 30% of the time. That means you will be losing some money 70% of the time. Does that still sound like a good plan?keenen said:... deal bust's percentage is 100% more than me ~
me bust = 0%
i mean... i will never bust... however .. the Bank will ~... if he bust then.. i win..Sonny said:That's not true at all. The dealer will not bust 100% of the time. They will probably only bust about 30% of the time. That means you will be losing some money 70% of the time. Does that still sound like a good plan?
-Sonny-
A 2d game, dealer stands on 17: Dealer busts 28% of the time, 72% of the time, he will have 17-21. Now. If. You. Think. You. Will. Beat. 17 to 21. 72%. Of. The. Time. Without. Hitting. Over 12. Then. Good. Luck.keenen said:i mean... i will never bust... however .. the Bank will ~... if he bust then.. i win..
but even tho he doesn't bust... it doesn't mean that i will lose .. right??